Saved Bookmarks
| 1. |
Factorise (a+b)cube+(b+C)cube+(a+C)-3(a+b)(b+c)(a+c) |
|
Answer» Step-by-step explanation: step 1: ASSIGN variable let (a+b) be x let (b+c) be y let (a+d) be z step:2: factorize using IDENTITY: x³+y³+z³- 3xyz = (x+y+z)(x²+y²+z²-xy -yz - xz) = (x+y+z)(x²+y²+z²-xy -yz - xz) step:3: final ANSWER ((a+b)+(c+b)+(a+c))(((a+b)²+(c+b)²+(a+c)²-(a+b)(c+b)-(c+b)(a+c)-(a+c)(a+b)) |
|