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Factorise a³-b³+1+3abstep by step with explaination pls |
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Answer» a³-b³+1+3ab To Find : factorise Solution:Use the formula : a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca) a³-b³+1+3ab = a³ + (-b)³ + 1³ + 3(a) (b) (1)= a³ + (-b)³ + 1³ - 3(a) (-b) (1) = (a - b + 1) ( a² + b² + 1² - a(-b) - (-b)(1) - (1)a)= (a - b + 1) ( a² + b² + 1 + ab + b - a) a³-b³+1+3ab = (a - b + 1) ( a² + b² + 1 + ab + b - a)Learn More:find the value of x by factorization, x2-8x+1280=0 - Brainly.in brainly.in/question/7343350 Using factor theorem, factorize each of the FOLLOWING polynomial ... brainly.in/question/15904651 Factorise: 1. a3 – 4a2 + 12 – 3a 2. a3x – x4 + A2X2 brainly.in/question/13142738 |
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