1.

Factorise by taking out Common Factor x(x+y)^3-3x^2y (x+y) ​

Answer»

Step-by-step EXPLANATION:

Answer

Given : x(x+y)

3

−3x

2

y(x+y)

TAKING x(x+y) as common in the given question,

we get, x(x+y)[(x+y)

2

−3xy]

We know that, (a+B)

2

=a

2

+b

2

+2ab

x(x+y)

3

−3x

2

y(x+y)=x(x+y)(x

2

+y

2

+2xy−3xy)

So we get,

x(x+y)

3

−3x

2

y(x+y)=x(x+y)(x

2

+y

2

−xy)


Discussion

No Comment Found

Related InterviewSolutions