Factorise each of the following. 16x ^5 - 144 x ^ 3

1.	Factorise each of the following. 16x ^5 - 144 x ^ 3
Answer» $\huge \underbrace \mathrm \purple{Answer}$ 16x5−144x3=16x3(x+3)(x−3) Step-by-step explanation: 16x^{5}-144x^{3}16x5−144x3 =16x^{3}\TIMES x^{2}-16x^{3}\times916x3×x2−16x3×9 =16x^{3}(x^{2}-9)16x3(x2−9) = 16x^{3}(x^{2}-3^{2})16x3(x2−32) =16x^{3}(x+3)(x-3)16x3(x+3)(x−3) /* By algebraic identity: \boxed {a^{2}-B^{2}=(a+b)(a-b)}a2−b2=(a+b)(a−b) Therefore, 16x^{5}-144x^{3}=16x^{3}(x+3)(x-3)16x5−144x3=16x3(x+3)(x−3) •••♪

Answer»

$\huge \underbrace \mathrm \purple{Answer}$

16x5−144x3=16x3(x+3)(x−3)

Step-by-step explanation:

16x^{5}-144x^{3}16x5−144x3

=16x^{3}\TIMES x^{2}-16x^{3}\times916x3×x2−16x3×9

=16x^{3}(x^{2}-9)16x3(x2−9)

= 16x^{3}(x^{2}-3^{2})16x3(x2−32)

=16x^{3}(x+3)(x-3)16x3(x+3)(x−3)

/* By algebraic identity:

\boxed {a^{2}-B^{2}=(a+b)(a-b)}a2−b2=(a+b)(a−b)

Therefore,

16x^{5}-144x^{3}=16x^{3}(x+3)(x-3)16x5−144x3=16x3(x+3)(x−3)

•••♪

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