Factorise :(i)16a2–254a2 (ii)16a2b–b16a2 (iii)100(x+y)2–81(a – InterviewSolution

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1.	Factorise :(i)16a2–254a2 (ii)16a2b–b16a2 (iii)100(x+y)2–81(a+b)2 (iv)(x–1)2–(x–2)2
Answer» Factorise : $(i) 16 a^{2} - \frac{25}{4 a^{2}}$ $(i i) 16 a^{2} b - \frac{b}{16 a^{2}}$ $(i i i) 100 (x + y)^{2} - 81 (a + b)^{2}$ $(i v) (x - 1)^{2} - (x - 2)^{2}$

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