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Factorise `(i) 27-125a^3-135a+225a^2` `(ii) 1-64a^3-12a +48a^2`. |
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Answer» We have `(i) 27-125a^3-135a+225a^2` `=3^3-(5a)^3-45(3-5a)` `=3^3-(5a)^3-(3xx3xx5a)(3-5a)`. `=(3-5a)^3=(3-5a)(3-5a)(3-5a)`. |
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