1.

Factorise `(i) 27-125a^3-135a+225a^2` `(ii) 1-64a^3-12a +48a^2`.

Answer» We have
`(i) 27-125a^3-135a+225a^2`
`=3^3-(5a)^3-45(3-5a)`
`=3^3-(5a)^3-(3xx3xx5a)(3-5a)`.
`=(3-5a)^3=(3-5a)(3-5a)(3-5a)`.


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