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Factorise using identity square 2xsquare -32x+78​

Answer»

Given \: Quadratic \: expression : \\2x^{2} - 32 x + 78

= 2( x^{2} - 16x+ 39 )

= 2[ x^{2} + ( -13 -3 )x + (-13)(-3)]

\underline { \blue { By \: Algebraic \: identity:}}

\boxed { \pink { x^{2} + (m+n)x + mn = (x+m)(x+n) }}

= 2(x-13)(x-3)

THEREFORE.,

\red { 2x^{2} - 32 x + 78 } \green { = 2(x-13)(x-3)}

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