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Factorise x^2–2xy+y^2–2(x–y)+1 |
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Answer» x2+y2−2xy=(x−y)2 x2+y2−2xy−1=(x−y)2−1=(x−y−1)∗(x−y+1) We THEREFORE have 2 factors: (x−y−1) and (x−y+1) Step-by-step explanation: |
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