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Factorise x^3-5x^2-2x+16 |
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Answer» (x-2){x-[(3/2)+(√41)/2]} {x-[(3/2)-(√41)/2]}Step-by-step explanation:if we put x=2 we get the EXPRESSION = 0.therefore, x-2 is a factor.x^3-5x^2-2x+16=(x-2)(x^2-3x-8).now for the ROOTS of quadratic expression.using formula, we get x= [3+√(9+32)]/2 =(3/2)+(√41)/2.x=[3-√(9+32)]/2. =(3/2)-(√41)/2.therefore,{x-[(3/2)+(√41)/2]} {x-[(3/2)-(√41)/2]} are the FACTORS of quadratic expression.therefore, the GIVEN expression FACTORIZES in(x-2){x-[(3/2)+(√41)/2]} {x-[(3/2)-(√41)/2]} |
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