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Factorise z cube - 12 + 4z |
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Answer» Factorise = z^2 -12+4z z^2+4z-12 By using quadratic FORMULA a= 1 ,b=+4 ,c= -12 D = b^2-4ac = 4×4-4×1×(-12) = 16-(-48 ) =16+48 =64Discriminant =64 x = -a+√D/ 2a , x= -a-√D/2a after PUTTING VALUEX= -4+8/2, x= -4-8/2 x=2 , x=-6 two factors are 2 and -6 |
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