Factorize: 4z2−8x+3(a) (2z−1)(2z−3)(b) (2z+1)(3−2z)(c) (2z+3)( – InterviewSolution

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1.	Factorize: 4z2−8x+3(a) (2z−1)(2z−3)(b) (2z+1)(3−2z)(c) (2z+3)(3z−1)(d) (z−1)(4z−3)
Answer» Factorize: $4 z^{2} - 8 x + 3$ $(a) (2 z - 1) (2 z - 3)$ $(b) (2 z + 1) (3 - 2 z)$ $(c) (2 z + 3) (3 z - 1)$ $(d) (z - 1) (4 z - 3)$

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