InterviewSolution
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InterviewSolution
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Factorize `9x^2+4y^2+16z^2+12xy-16yz-24xz`. |
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Answer» We observe here that `-16yz and -24 xz` are negative terms in the given expression and z occruws in both the terms . So, we write ` 16z^2 "as " (-4z)^2`. Thus , we have `9x^2+4y^2-4xy-12yz+6xz` ` =(3x)62+(2y)^2+(-4z)^2+{(2xx(3x)xx (2y)}+{2xx(2y)xx(-4z)}+{2xx(-4z)xx(3x)}` `={3x+2y+(-4z)^2}=(3x+2y-4z)^2`. |
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