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Factorize `(i) (x^2-(y^2)/(100))` `(ii)(100-9x^2)` `(iii)(49x^2-(1)/(4))` |
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Answer» We have ` (i) (x^2-(y^2)/(100))=x^2-((y)/(10))^2` `therefore (x^2-(y^2)/(100))=(x-(y)/(10))(x+(y)/(10))`. ` (ii) (100-9x^2)=(10)^2-(3x)^2` `=(10-3x)(10+3x)` `therefore (100-9x^2)=(10-3x)(10+3x)`. `(iii) (49x^2-(1)/(4))=(7x)^2-((1)/(2))^2` `=(7x-(1)/(2)) (7x+(1)/(2))` `therefore (49x^2-(1)/(4)) =(7x-(1)/(2))(7x+(1)/(2))`. |
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