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Factroise `(i) a^3+b^3+a+b` `(ii) a^3-b^3-a+b` |
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Answer» We have `(i) a^3+b^3+a+b` `=(a^3+b^3)+(a+b)` `=(a+b)(a^2-ab+b^2)+(a+b)` `=(a+b)xx{(a^2-ab+b^2)+1}` `=(a+b)(a^2-ab+b^2+1)`. `therefore (a^3+b^3+a+b)=(a+b)(a^2-ab+b^2+1)`. `(ii) a^3-b^3-a+b` `=(a^3-b^3)-(a-b)` `=(a-b)(a^2+ab+b^2)-(a-b)` `=(a-b)(a^2+ab+b^2 -1)`. `therefore (a^3-b^3-a+b)=(a-b)(a^2+ab+b^2-1)`. |
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