Factroize `(i) (x^3-x)` `(ii) 18a^2x^2-32)` `(iii) (2a^5-32a)`.

1.	Factroize `(i) (x^3-x)` `(ii) 18a^2x^2-32)` `(iii) (2a^5-32a)`.
Answer» We have `(i) (x^3-x)=(x^2 -1)` `=x(x-1)(x+1)` `therefore(x^3-x)=x(x-1)(x+1)`. `(ii) (18a^2x^2-32) =2(9a^2x^2-16)` ` =2xx[(3ax)^2-4^2]` ` =2(3ax-4)(3ax+4)` `therefore (18a^2x^2-32)=2(3ax-4)(3ax+4)`. `(iii) (2a^5-32a)=2a(a^4-16)` `=2axx [(a^2)^2-4^2]` ` =2a(a^2-4)(a^2+4)` ` =2a (a-2)(a+2)(a^23+4)` ` therefore (2a^5-32a)=2a(a-2)(a+2)(a^2+4)`

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