Father’s age is 4 years more than twice the age of his son. If the s

1.	Father’s age is 4 years more than twice the age of his son. If the sum of the ages offather and his son is 46 years. What is the present age of son?
Answer» GIVEN : ⬤ Father age is 4 YEARS more than TWICE the age of his Son . ⬤ SUM of their ages is 46 years . To Find : ⬤ Present Age of Son . Solution : Let : Age of Son = x Age of Father = 2x + 4 $\sf{x+2x+4=46}$ 3x + 4 = 46 3x = 46 - 4 3x = 42 x = 42/3 x = 14 Therefore , The Value of x is 21 . HENCE , Age of Son = x = 14 Age of Father = 2x + 4 = 2(14) + 4 = 28 + 4 = 32 Therefore , Age of Son is 14 years and Age of Father is 32 years .

Father’s age is 4 years more than twice the age of his son. If the sum of the ages offather and his son is 46 years. What is the present age of son?

Answer»

⬤ Father age is 4 YEARS more than TWICE the age of his Son .

⬤ SUM of their ages is 46 years .

⬤ Present Age of Son .

Let :

$\sf{x+2x+4=46}$

3x + 4 = 46

3x = 46 - 4

3x = 42

x = 42/3

x = 14

Therefore , The Value of x is 21 .

Age of Son = x

= 14

Age of Father = 2x + 4

= 2(14) + 4

= 28 + 4

= 32

Therefore , Age of Son is 14 years and Age of Father is 32 years .