Fe^(2+) (aq)+NO_(3)^(-) (aq)+H_(2)SO_(4) (conc.) to Brown ring The br – InterviewSolution

1.	Fe^(2+) (aq)+NO_(3)^(-) (aq)+H_(2)SO_(4) (conc.) to Brown ring The brown ring is due to the formation of complex, [Fe(H_(2)O)_(5)NO]SO_(4). What is the oxidation state of iron in the complex ?
Answer» Solution :Here `NO` is `NO^(+)`, so in `[Fe(H_(2)O)_(5)NO^(+)]^(2+)`, the oxidation state of IRON is `+1`

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