1.

Fe^(2+) does not give prussian blue colour with K_4[Fe((CN)_6], but on its reaction with (X), prussian blue colour appears with the reagent (X) is :

Answer»

`MnO_4^(-)//H^+`
`H_2SO_4`
`NH_3`
All true

Solution :`MnO_4 H^(+) to[O] : FE^(2+)OVERSET([O])toFe^(3+)+[Fe(CN)_6]^(4-)to Fe_4[Fe(CN)_6]_3`


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