1.

Fe_(2)(SO_(4))_(3) is used in water and sewage treatment to aid the removal of suspended impurities. Calculate the mass percentage of iron, sulphur and oxygen in this compound.

Answer»


Solution :`"MOL. MASS of "Fe_(2)(SO_(4))_(3)=2xx56+(32+64)xx3=400`
`%" of FE"=(2xx56)/(400)xx100=28%","%" of S"=(32xx3)/(400)xx100=24%,""%" of O"=(4xx16xx3)/(400)xx100=48%`


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