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[Fe(CN)_5NO]^(2-)+S^(2-)toProduct[X] Answer the following questions for the product [X]. (i)Number of negative monodenate ligand(s). (ii)Effective atomic number of iron in the complex. (iii)Number of unpaired electrons

Answer»


Solution :(i)five `CN^(-)` and ONE `NOS^(-)`=6
(ii)Iron is in +2 OXIDATION state and atomic number of iron is 26.
Therefore, EAN=24+12=36
(iii)`Fe^(2+)=3d^(5)4s^(0)`

`CN^-` is strong FIELD ligand which compels for paring of electron. Therefore , there is one unpaired electron.


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