1.

[Fe(H_(2)O)_(5)NO]^(2+) is a complex formed in the brown ring test for NO_(3)^(-) ion. In this complex.

Answer»

NO TRANSFERS its electronto `Fe^(2+)` so that we have iron as `Fe(I)` and NO as `NO_^(+)`
There are three unpaired electron so that its magnetic moment is 3.87 B.M.
The colour is due to chargetransfer
All the above statements are correct.

Solution :`HgI_(2)overset(Delta)(RARR) Hg_ I_(2) ("VIOLET vapours")`
`NO rarr NO^(+) + E^(-)`,
`{:(Fe^(2+) ,+,e^(-),rarr,Fe^(+)),((3d^(6)),,,,(3d^(7))),("4 unpaired "e^(-),,,,"3 unpaired "e^(-)):}`
`mu` for `Fe^(+) = sqrt(n(n+2))= sqrt(3 xx 5)` BM
`= sqrt(15) BM =3.87 BM`


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