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Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide. |
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Answer» Solution :Let the number of `O^(2-)` IONS in the packing= N Number of octahedral holes (voids) =N Voids occupied by `FE^(3+)= (2N)/(3)` Ratio of `Fe^(3+) : O^(2-)= (2N)/(3): N` `=2:3` Formula of ferric OXIDE = `Fe_(2)O_(3)` |
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