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Ferrochrome, an iron chromium alloy used in making stainless steel, is produced by reducing chromite (FeCr_(2)O_(4)) with coke : FeCr_(2)O_(4)(s) + 4C (s) rarr underset("Ferrochrome")(underbrace(Fe(s) + 2Cr(s))) + 4CO(s) (i) How many kilograms of chromium can be obtained by the reaction of 236 kg of chromite with an excess of coke ? (ii) How many litres of CO at 25^(@)C and 740 mm Hg are obtained as a by-product ? |
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Answer» Solution :(i) `FeCr_(2)O_(4)(s) + 4C(s) rarr Fe(s) + 2Cr(s) + 4CO(s)` 224 KG of chromite gives = 104 kg of Cr 236 Kg of chromite gives `= (104 XX 236)/(224)` kg of Cr = 109.57 kg Cr (ii) 224 kg chromite gives = 112 Kg CO Thus 236 kg chromite gives `= (112 xx 236)/(224)` kg CO `rArr` 118 kg CO = 4214.2857 mol. As PV = nRT T = 298 K `P = (740)/(760)` atm `therefore""V = (nRT)/(P) = (4214.28 xx 0.0821xx 298 xx 760)/(740)` `= 105.89 xx 10^(3)` litre |
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