1.

FeSO_(4) is a very good absorber for NO, the new compound formed by this process is found to contain number of unpaired electrons:

Answer»

4
5
3
6

Solution :`Fe^(3+)(aq)+NO+SO_(4)^(2-)(aq) to [Fe(H_(2)O)_(5)(NO)]^(2+)+SO_(4)^(2-)`
`mu_(E f f)=3.89` BM
HENCE, no of unpaired electron=3.


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