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FeSO_(4) solution mixed with (NH_(4))_(2)SO_(4) solution in 1:1 molar ratio gives the test of Fe^(2+)ion but CuSO_(4) solution mixed with aqueous ammonia in 1:4molar ratio does not give the test of Cu^(2+) ion. Explain why? |
| Answer» SOLUTION :When `FeSO_(4)` solution is mixed with `(NH_(4))_(2)SO_(4)` solution in `1:1` molar ratio, a double salt, `FeSO_(4).(NH_(4))_(2)SO_(4).6H_(2)O` (Mohr salt), is formed. It dissociates completely in the solution to form the COMPONENT IONS `(Fe^(2+), NH_(4)^(+), SO_(4)^(2-))`. Thus, the solution gives the tests of `Fe^(2+)` ion. When `CuSO_(4)` solution is mixed with aqueous ammonia in `1:4` molar ratio, a coordination compound with the formula, `[Cu(NH_(3))_(4)]SO_(4)`, is formed. It ionises in the solution to form the complex cation `[Cu(NH_(3))_(4)]^(2+)`, which does not DISSOCIATED further to produce `Cu^(2+)` ions. Hence it does not give the tests of `Cu^(2+)` ion. | |