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FeSO_(4) solution mixed with (NH_(4))_(2)SO_(4) solution (in molar ratio 1 : 1) gives the test of Fe^(2+) ion but CuSO_(4) solution mixed with liquid NH_(3) (in the molar ratio 1 : 4) does not give the test of Cu^(2+).Explain why. |
| Answer» Solution :`FeSO_(4)` solution does not FORM any complex with `(NH_(4))_(2)SO_(4)`. INSTEAD, they form a double salt, `FeSO_(4).(NH_(4))_(2)SO_(4).6H_(2)O` which dissociates COMPLETELY into ions in the solution. But `CuSO_(4)` combines with `NH_(3)` to form the complex `[Cu(NH_(3))_(4)]SO_(4)` in which the complex ion `[Cu(NH_(3))_(4)]^(2+)` does not dissociate to give `Cu^(2+)` ions. | |