1.

FexO contains one Fe(III) for every three Fe(II). What is x?

Answer»

`2/3`
`8/9`
`3/4`
`5/3`

Solution :Let Number of `FE^(3+)` IONS = y
Number of `Fe^(3+)` ions = 3y
`thereforey + 3y = x thereforex = 4Y`
`FEXO` us electrically NEUTRAL, hence we get,
`3(y) = 3(3y) = 2 xx 1 `
`3y + 6y = 2`
`9y = 2`
`y = 2/9`
`y = 2/9`
`x = 4 cdot (2/9) = 8/9`.


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