1.

Figure show two reservoirs containing two liquids of masses 4m and 2m and their specific heat capacities are S and 2S respectively. Their initial temperatures are 4T_(0) and T_(0) respectively. The containers are joinedby a conducting K, length l and cross section area A specific heat capacity of the rod is negligible.

Answer»

The TEMPERATURE of mid-point `'P'` of the ROD is always constant.
Heat extracted from container `1=` Heat supplied to container 2
After time `t_(0)=(2msl)/(ka)In2` the temperature difference between CONTAINERS becomes half of the initial temperature difference.
After time `t_(0)=(msl)/(ka)In2` the temperature difference between containers becomes half of the initial temperature difference.

Solution :`dQ=(4m)s(-dT_(1))=(2m)(2s)dT_(2)`
On solving we get `/_\T_(F)=/_\T_(i)e^((-KAt)/(2msl))`
Temperature of point `P` remains constant


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