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Figure shows a long wire bent at the middle to form a right angle. Show that the magnitudes of the magnetic field at point P, Q,R and S are equal and find this magnitude. |
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Answer» `|B_P|=(mu_0i)/(4pid), |B_R|=(mu_0i)/(4pid)` At P and R, the field due to vetical part is zero and the points are equidistant form the horizontal wire. Similarly, the point S and Q are equidistant from the vertical wire and field due to horizontal wire is zero. Hence `|B_Q|=|B_S|=(mu_0i)/(4pid)` `implies |B_P|=|B_Q|=|B_R|=|B_S|=(mu_0i)/(4pid)` |
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