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Figure shows a plot of where V is the accelerating potential. The de-Broglie wavelength 'λ' in the case of two particles having same charge 'q' but different masses m, and mz. Which line (A or B) represents a particle of larger mass ? |
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Answer» Solution :`LAMBDA=(h)/(sqrt2meV)` `lambda_(A)=(h)/(sqrt2m_(A)qV_(A))` `lambda_(B)=(h)/(sqrt2Me_(B)eV_(B))=(h)/(sqrt2M_(B)qV_(B))` `SQRT((2m_(B)qV_(B))/(2m_(A)qV_(A)))=sqrt((m_(B)V_(B))/(m_(A)V_(A)))` `(lambda_(A))/(sqrtV_(A))=(lambda_(B))/(sqrtV_(B))` `m_(A)< m_(B)` |
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