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Figure shows a ray of light passing through a prism. If the refracted ray QR is parallel to the base BC, show that (i) r_(1) = r_(2) = A//2, (ii) angle of minimum deviation, D or D_(m) = 2i -A. |
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Answer» SOLUTION :(i) From give figure, `A = r_(1) + r_(2)` As RAY QR is parallel to the base BC, then `r_(1) = r_(2)`, and i = E Therefore, `2r_(1) ` ( or `2r_(2)) = A` `rArr r_(1) = r_(2) = A//2` (ii) `D = x+y``D = ( i - r_(1)) + ( e- r_(2))` `D = ( i +e ) - ( r_(1) + r_(2))` or`D = 2i -A` |
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