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Figure shows a series LCR circuit connected to a variable frequency 230 V source. The source frequency which drives the circuit the circuit in resonance isA. 4 HzB. 5 HzC. 6 HzD. 8 Hz |
Answer» Correct Answer - D Here, `L=5 H,C = 80 mu F = 80xx10^(-6)F, R = 40 Omega` `V_("rms")=230 V` The resonannt angular frequency is `omega_(r )=(1)/(sqrt(LC))=(1)/(sqrt(5xx80xx10^(-6)))=50" rad " s^(-1)` `therefore upsilon_(r )=(omega_(r ))/(2pi)=(50)/(2pi)=8 Hz` |
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