InterviewSolution
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InterviewSolution
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Figure shows a uniform smooth solid cylinder `A` of radius `4 m` rolling without slipping on the `8 kg` plank which, in turn, is supported by a fixed smooth surface. Block `B` is known to accelerate down with `6 m//s^(2)` and block `C` moves down with acceleration `2 m//s^(2)`. What is the angular acceleration of the cylinder?A. `4/5rads^(-2)`B. `6/5 rads^(-2)`C. `2rads^(-2)`D. `1 rads^(-2)` |
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Answer» Correct Answer - D Acceleration of the bottom of the cylinder = acceleration of the plank `=2m//s^(2)` towards the right Acceleration of the top of te cylinder = acceleration of `B=6m//s^(-2)` towards the left Let linear acceleratiion of the cylinder be a towards the left and angular acceleration of it `alpha` in an anticlockwise sense. writing constraint, we get `a+Ralpha=6` and `Ralpha-a=2` `impliesalpha=1rads^(-2),a=2m//s^(2)` |
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