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Figure shows as thin tube open at one end rotating with constant angular speed omega. The other end of the tube has a small opening. Tube contains a fluid of density rho which effuses with speed u relative to the tube. Let rho_(A) be the pressure at the point in the tube just behind the opening. Assume the atmospheric pressure to be p_(0) and pick correct option(s) for the instant when h=l/2 |
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Answer» <P>`p_(A)=p_(0)+(rho omega^(2)l^(2))/4` `(p_(A)-p_(0))s=rhoshomega^(2)(l-h/2)` `impliesp_(A)=p_(0)+rho omega^(2)h(l- h/2)` By Bernoulli's equation `u=omegasqrt(2h(l-h/2))` 
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