1.

Figure shows crosssection view of a infinite cylindrical wire with a cavity, current density is uniform vec(j)=-j_(0)hat(k) as shown in figure

Answer»

magnetic field inside cavity is uniform
magnetic field inside cavity is along `vec(a)`
magnetic field inside cavity is perpendicular to `vec(a)`
If an electron is PROJECTED with velocity `v_(0)hat(j)` inside the cavity it will MOVE undeviated.

Solution :Magnetic field is GIVEN by `vec(B) =(mu_(0)(vec(j)xxvec(a)))/2`


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