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Figure shows the stopping potential (V_(0)) for the photo electron vers ((1)/(lambda)) graph, for two metals A and B, lambda being the wavelength of incident light. How is the value of Planck's constant determined from the graph ? |
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Answer» SOLUTION :We know that `V_(0)=(h)/(e ) (v-v_(0))= (hc)/(e ) ((1)/(lambda)-(1)/(lambda_(0)))`. So `V_(0)- (1)/(lambda)` graph is a straight line graph whose SLOPE has a magnitude of`(hc)/(e )` . Thus, Planck.s constant`h= (e )/(C )xx ("Slope of " V_(0)-(1)/(lambda)` aph for any photosensitive METAL) |
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