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Fiind the value of K if (2×-1) is a factor of 6ײ + K×-2 |
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Answer» K = 1 Step-by-step explanation: (2x-1) is a factor of 6x²+kx-2 X = 1/2 is a factor of 6x²+kx-2 Putting the VALUE of x, 6(1/2)²+k(1/2)-2 = 0 6×1/4 + k/2 -2 = 0 3/2+k/2-2 = 0 3+k/2 - 2 = 0 3+k/2 = 2 3+k = 4 K = 1 Hope it helps!! Thank you ✌️ |
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