1.

Fill in the blanks :(i) 42 x 0 = ……….(ii) 592 x 1 = ………..(iii) 328 x 573 = ……….. x 328(iv) 229 x ………… = 578 x 229(v) 32 x 15 = 32 x 6 + 32 x 7 + 32 x ……….(vi) 23 x 56 = 20 x 56 + ……… x 56(vii) 83 x 54 + 83 x 16 = 83 x ( ……….. ) = 83 x ………….. = …………(viii) 98 x 273 – 75 x 273 = ( …………. ) x 273 = ………… x 273

Answer»

(i) 42 x 0 = 0

(By closure property 0)

(ii) 592 x 1 = 592

(By closure property 1)

(iii) 328 x 573 = 573 x 328

(By commutative law of multiplication)

(iv) 229 x 578 = 578 x 229

(By commutative law of multiplication)

(v) 32 x 15 = 32 x 6 + 32 x 7 + 32 x 2

(By commutative law of multiplication)

(vi) 23 x 56 = 20 x 56 + 3 x 56

(By Distributive law of multiplication)

(vii) 83 x 54 + 83 x 16 = 83 x (54 + 16) = 83 x 70 = 5810

(viii) 98 x 273 – 75 x 273 = (98 – 75) x 273 = 23 x 273



Discussion

No Comment Found

Related InterviewSolutions