InterviewSolution
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                                    Fill in the blanks :(i) 42 x 0 = ……….(ii) 592 x 1 = ………..(iii) 328 x 573 = ……….. x 328(iv) 229 x ………… = 578 x 229(v) 32 x 15 = 32 x 6 + 32 x 7 + 32 x ……….(vi) 23 x 56 = 20 x 56 + ……… x 56(vii) 83 x 54 + 83 x 16 = 83 x ( ……….. ) = 83 x ………….. = …………(viii) 98 x 273 – 75 x 273 = ( …………. ) x 273 = ………… x 273 | 
                            
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Answer»  (i) 42 x 0 = 0 (By closure property 0) (ii) 592 x 1 = 592 (By closure property 1) (iii) 328 x 573 = 573 x 328 (By commutative law of multiplication) (iv) 229 x 578 = 578 x 229 (By commutative law of multiplication) (v) 32 x 15 = 32 x 6 + 32 x 7 + 32 x 2 (By commutative law of multiplication) (vi) 23 x 56 = 20 x 56 + 3 x 56 (By Distributive law of multiplication) (vii) 83 x 54 + 83 x 16 = 83 x (54 + 16) = 83 x 70 = 5810 (viii) 98 x 273 – 75 x 273 = (98 – 75) x 273 = 23 x 273  | 
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