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Fina area of a triangle whose sides are 6cm, 8cm, 10cm, |
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Answer» Answer: 24cm2 Step-by-step EXPLANATION: The AREA of a triangle with sides of length 6 cm , 8 cm and 10 cm has to be determined. Looking at the length of the sides NOTICE that 6^2 + 8^2 = 36 + 64 = 100 = 10^2. This is a RIGHT triangle with perpendicular sides of length 6 and 8 cm. The area of the triangle is (1/2)*6*8 = 24 cm^2. The area can also be derived using Heron's theorem. The area is given by sqrt(s*(s - a)*(s -B)*(s-c)) where s is the semi-perimeter equal to (6+8+10)/2 = 12 , a = 6, b = 8 and c = 10. The area of the triangle is equal to sqrt(12*6*4*2) = sqrt(576) = 24 cm^2. |
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