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Find=(2a-3b)^3+(b-2c)^3+8(c-a)^3*PLZ TELL FAST* |
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Answer» The given equation is,(2A - b)³ + (b - 2c)³ + 8(c - a)³= (2a - b)³ + (b - 2c)³ + (2c - 2a)³Let X = (2a - b) ; y = (b - 2c) ; z = (2c - 2a)Now,x + y+ z = (2a - b) + (b - 2c) + (2c - 2a) = 0Since, x + y + z = 0, then,x³ + y³ + z³ = 3xyz⇒ (2a - b)³ + (b - 2c)³ + (2c - 2a)³ = 3(2a - b) (b - 2c) (2c - 2a)⇒ (2a - b)³ + (b - 2c)³ + 8(c - a)³ = 6(2a - b) (b - 2c) (c - a) |
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