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Find a and b if a^2+b^2+400-2ab-40a-40b |
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Answer» Answer: PLS mark me as brainliest Step-by-step EXPLANATION: a+b = 40 ----------(1) a = 40-b (a+b)² = 400 a²+b²+2ab = 400 --------(2) Putting the value of 'a' in equation (1) (40-b)² + b² + 2(40-b)(b) = 400 40²+(-b)²-2(40)(-b)+b²+2(40-b)(b)=400 1600+b²+80b+b²+(80-2b)(b) = 400 1600+b²+b²+80b+80b-2b² = 400 1600+2b²-2b²+80b = 400 1600+80b = 400 80b = 400-1600 80b = -1200 b = -1200/80 b = -15 Putting the value of 'b' in equation (1): a + (-15) = 40 a= 40 + 15 a = 55 Simple the answer is 0 ZERO, because in a algebric expression equal- to is given when both the sides of the expression is equal. |
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