1.

Find a and b if a^2+b^2+400-2ab-40a-40b​

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Answer: PLS mark me as brainliest

Step-by-step EXPLANATION:

a+b = 40 ----------(1)

a = 40-b

(a+b)² = 400

a²+b²+2ab = 400 --------(2)

Putting the value of 'a' in equation (1)

(40-b)² + b² + 2(40-b)(b) = 400

40²+(-b)²-2(40)(-b)+b²+2(40-b)(b)=400

1600+b²+80b+b²+(80-2b)(b) = 400

1600+b²+b²+80b+80b-2b² = 400

1600+2b²-2b²+80b = 400

1600+80b = 400

80b = 400-1600

80b = -1200

b = -1200/80

b = -15

Putting the value of 'b' in equation (1):

a + (-15) = 40

a= 40 + 15

a = 55

Simple the answer is 0 ZERO, because in a algebric expression equal- to is given when both the sides of the expression is equal.



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