1.

Find a, b and c such that the following numbers are in AP: a, 7, b, 23, c.

Answer»

For a, 7, b, 23, c… to be in AP

it has to satisfy the condition,

a5 – a4 = a4 – a3 = a3 – a2 = a2 – a1 = d

Where d is the common difference

7 – a = b – 7 = 23 – b = c – 23 …(1)

Let us equate,

b – 7 = 23 – b

2b = 30

b = 15 (eqn 1)

And,

7 – a = b – 7

From eqn 1

7 – a = 15 – 7

a = – 1

And,

c – 23 = 23 – b

c – 23 = 23 – 15

c – 23 = 8

c = 31

So a = – 1

b = 15

c = 31

Then, we can say that, the sequence – 1, 7, 15, 23, 31 is an AP



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