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Find a, b and c such that the following numbers are in AP: a, 7, b, 23, c. |
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Answer» For a, 7, b, 23, c… to be in AP it has to satisfy the condition, a5 – a4 = a4 – a3 = a3 – a2 = a2 – a1 = d Where d is the common difference 7 – a = b – 7 = 23 – b = c – 23 …(1) Let us equate, b – 7 = 23 – b 2b = 30 b = 15 (eqn 1) And, 7 – a = b – 7 From eqn 1 7 – a = 15 – 7 a = – 1 And, c – 23 = 23 – b c – 23 = 23 – 15 c – 23 = 8 c = 31 So a = – 1 b = 15 c = 31 Then, we can say that, the sequence – 1, 7, 15, 23, 31 is an AP |
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