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Which term of the AP 3, 8, 13, 18, …will be 55 more than its 20th term? |
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Answer» Given AP is 3, 8, 13, 18,… First term = a = 3 Common difference = d = 8 – 3 = 5 And n = 20 and a20 be the 20th term, then a20 = a + (n – 1)d = 3 + (20 – 1) 5 = 3 + 95 = 98 The required term = 98 + 55 = 153 Now, 153 be the nth term, then an = a + (n – 1)d 153 = 3 + (n – 1) x 5 153 – 3 = 5(n – 1) 150 = 5(n – 1) n – 1 = 30 n = 31 Required term will be 31st term. |
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