1.

Find a formula for maximum height attained by object.

Answer» Solution: Form 3rd equation of motion
`v^(2)=u^(2)+2as`
`v=0,a=-g`
`:.0^(2)=u^(2)+2(-g)s`
`2gs=u^(2)`
`s=(u^(2))/(2g)`


Discussion

No Comment Found

Related InterviewSolutions