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Find ‘a’ if the distance between the points (a, 2) and (3, 4) is V8 units. |
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Answer» Let P = (a, 2) and Q = (3, 4) By data |PQ| = √8 ⇒ √8 = √((3 - a)2 + (4 - 2)2) ⇒ 8 = (3 – a)2 + 22 = 8 ⇒ 9 + a2 – 6a + 4 ⇒ a2 – 6a + 5 = 0 ⇒ (a – 5)(a – 1) = 0 ⇒ a = 5 or a = 1 |
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