1.

Find a quadratic polynomial each with the given numbers as the zeros of the polynomials. √3,3√3​

Answer»

<P>Given that zeros are

\sf\alpha  =  \sqrt{3}  \\  \\  \sf \beta  = 3 \sqrt{3}

\sf  SUM  \: OF  \: ROOTS = s =  \alpha  +  \beta  \\  \\  =  \sf \sqrt{3}  + 3 \sqrt{3}  \\  \\  \sf = 4 \sqrt{3}  \\  \\ \sf PRODUCTS  \:  OF  \: ROOTS = p =  \alpha  \beta  \\  \\  =  \sf \sqrt{3}  \times 3 \sqrt{3}  = 9

We KNOW that quadratic POLYNOMIAL WHOSE sum is roots is s and product of roots is p is given by

\sf  {x}^{2}   - sx + p

So

REQUIRED Polynomial is

\sf {x}^{2}  - 4 \sqrt{3}  \:x + 9



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