1.

Find a relation between x and y such that the point (x ,y) is equidistant from the points (7, 1) and (3, 5).

Answer» PB=PC
`sqrt((x-7)^2+(y-1)^2)=sqrt((x-3)^2+(y-5)^2)`
squaring both sides and solving it
`x^2-14x+49+y^2-2y+1=x^2-6x+9+y^2-10y+25`
`8y+16=8x`
`y=x-2`


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