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Find (a) the average and (b) mis value for the Saw tooth voltage of peak value Vas shown in the figure |
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Answer» Solution :As the equation of the Saw-tooth WAVE SHOWN in the figure will be `V=(2V_(@))/(T)t-V_(@)=V_(@)((2ty)/(T)-(1))` `So,(a)V_av=(int_(0)^(T//2)(Vdt)/(int_(0)^(T//2)=(2)/(T)int_(@)^(T//2)V_(@)(2t)/(T)-1)DT=|V_(@)/(2)` `and(B)V_(rms)[int_(@)^(T)V^(20dt)/(Int_(@)^(T)dt]]^(1//2)=(V_(@))/(sqrt3)` |
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