1.

Find a vector in the direction of vector 2i - 3j  + k6 which has magnitude 21 units.

Answer»

Required vector 

= 21((2i - 3j + 6k)/√(4 + 9 + 36)) = 21((2i - 3j + 6k)/√49)

= 21((2i - 3j + 6k)/7) = 3(2i - 3j + 6k) = 6i - 9j + 18k



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