1.

Write the length (magnitude) of a vector whose projections on the coordinate axes are 12, 3 and 4 units.

Answer»

Since Lx=12, Ly=3 and Lz=4 are given, we can find out L by

L 2= Lx+ Ly+ Lz2

=12+ 3+ 42

=144 + 9 + 16 = 169

Hence L=13 units.



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