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    				| 1. | Write the length (magnitude) of a vector whose projections on the coordinate axes are 12, 3 and 4 units. | 
| Answer» Since Lx=12, Ly=3 and Lz=4 are given, we can find out L by L 2= Lx2 + Ly2 + Lz2 =122 + 32 + 42 =144 + 9 + 16 = 169 Hence L=13 units. | |